after applying a filter -i design- to a real signal, it returns complex signal after ifft

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[x,fs]=audioread('some.wav');
n=length(x);
t = ((0:n-1)*(fs/n));
y=fft(x);
f = ((0:n-1)*(fs/n));
y0 = fftshift(y);
f0 = ((-n/2:n/2-1)*(fs/n));
noise = find(abs(y0) == max(abs(y0)));
noiseW= [2*pi*f0(noise(1)) 2*pi*f0(noise(2))];
z1=exp(1i*noiseW(1));
z2=exp(1i*noiseW(2));
z=exp(1i*2*pi*f0);
H=(1-z1*(z.^-1)).*(1-z2*(z.^-1));
out0=y0.*(H.');
out=ifftshift(out0);
signal=ifft(out);
audiowrite('output.wav',final,fs);
  2 comentarios
Daniel Pollard
Daniel Pollard el 14 de Mayo de 2021
I'm not sure I understand the problem. The FFT (and the IFFT) produce complex outputs by their definition. Could you give some more details? What were you expecting to happen?
Hamza AKYILDIZ
Hamza AKYILDIZ el 14 de Mayo de 2021
some.wav file is a real signal. after i apply the filter H to it, i expect it to be still real after ifft.

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Respuesta aceptada

Paul Hoffrichter
Paul Hoffrichter el 14 de Mayo de 2021
Your imaginary part only is non-zero due to the usual floating point roundoffs and truncations. Fix this using round:
signal=ifft(out);
signalRound = round(signal, 10);

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