problem in cell matrix operations

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Pooneh Shah Malekpoor
Pooneh Shah Malekpoor el 14 de Mayo de 2021
Respondida: Walter Roberson el 14 de Mayo de 2021
Hello
I have code like this which gives out a 5*1 cell matrix:
row = [0; 1; 2; 3; 4] ;
Coh = [15;16 ;17; 18; 20;19;7;8;22;25] ;
N = length(A) ;
Csurf = cell(N,1) ;
for i = 1:N
if row(i) == 0
Csurf{i} = 0 ;
else
Csurf{i} = Coh(1:row(i)) ;
Coh(1:row(i)) = [] ;
end
end
end
----------------------------------------------------
Now imagine that both row and Coh become cell matrices by the below repmat command,
Nmc=2
BB = repmat({row},Nmc,1);
CV=repmat({Coh},Nmc,1);
I have to write a code which considers the first cell of both BB and CV together and do the calculations as in the first code and then consider the second cell of BB and CV together and do the same calculations. The result would be a 5*2 cell matrix as Nmc=2. How should i formulate this?should i define a for loop? i am not good at cell indexing!
Any help is highly appreciated.
  1 comentario
Adam Danz
Adam Danz el 14 de Mayo de 2021
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Walter Roberson
Walter Roberson el 14 de Mayo de 2021
Your current code would take 1 row from Coh, then the following 2 rows, then the following 3 rows, and so on. Is that what is desired?
If it is, then consider using mat2cell() . mat2cell() even handles counts of 0.
row = [0; 1; 2; 3; 4] ;
Coh = [15;16 ;17; 18; 20;19;7;8;22;25] ;
mat2cell(Coh, row, 1)
ans = 5×1 cell array
{0×1 double} {[ 15]} {2×1 double} {3×1 double} {4×1 double}

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