Proper Formatting in the 'fprintf' function

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Zach Pacheco
Zach Pacheco el 25 de Jul. de 2013
I'm attempting to align certain text in a text file that I'm writing with matlab. Right now part of my code looks like this:
'%6.4f\tTwFAM1Sh(2) - Mode 1, coefficient of x^2 term\r\n' ...
'%6.4f\tTwFAM1Sh(3) - , coefficient of x^3 term\r\n' ... ''%6.4f\tTwFAM1Sh(4) - , coefficient of x^4 term\r\n' ...
'%6.4f\tTwFAM1Sh(5) - , coefficient of x^5 term\r\n' ...
and it prints this:
1.4401 TwFAM1Sh(2) - Mode 1, coefficient of x^2 term
-0.4228 TwFAM1Sh(3) - , coefficient of x^3 term
-0.0239 TwFAM1Sh(4) - , coefficient of x^4 term
0.0027 TwFAM1Sh(5) - , coefficient of x^5 term
but what I need it to do is this:
0.8164 TwFAM1Sh(2) - Mode 1, coefficient of x^2 term
0.3370 TwFAM1Sh(3) - , coefficient of x^3 term
-0.3668 TwFAM1Sh(4) - , coefficient of x^4 term
0.4695 TwFAM1Sh(5) - , coefficient of x^5 term
...The second part prints the numbers aligned from the last integer rather than aligning the first integer. Any guesses??

Respuesta aceptada

Cedric
Cedric el 25 de Jul. de 2013
Editada: Cedric el 25 de Jul. de 2013
Right justification is the default and you would have to use '-' to enforce left justification. The issue with your code is that with the precision of 4 that you set up, negative numbers lead to a field width larger than 6. For what you are trying to achieve, what about increasing the field width? Illustration:
>> fprintf('%7.4f\n', [pi, -pi]) ;
3.1416
-3.1416
>> fprintf('%-7.4f\n', [pi, -pi]) ;
3.1416
-3.1416
or decreasing the precision..
>> fprintf('%6.3f\n', [pi, -pi]) ;
3.142
-3.142
  3 comentarios
Cedric
Cedric el 25 de Jul. de 2013
What I am showing with +/-pi is that it works for both when the field width is large enough for the negative sign, precisely because there is this right alignment by default.
Zach Pacheco
Zach Pacheco el 25 de Jul. de 2013
Increasing the field width worked!! Thank you very much

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