how to solve this nonlinear equation?

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Pritha
Pritha el 21 de Mayo de 2021
Editada: Torsten el 22 de Mayo de 2021
m = 4.7542;
gsms = 12.684 ;
m1 = (m - gss);
p = 0.1 : 0.5 : 10 ;
k = (3 * p * pi^2 / 2)^(1/3) ;
k1 = sqrt(k^2 + m1^2);
F = (gsms * m1 * (k1 - m1^2/2 *log((k1+k)/m1))/pi^2 )-gss ;
  2 comentarios
Tayyab Khalil
Tayyab Khalil el 21 de Mayo de 2021
Can you clearly desribe which equation you want to solve and for which variable?
Dyuman Joshi
Dyuman Joshi el 21 de Mayo de 2021
What is gss?
Also, you have defined k and k1 incorrectly, use elementwise operators (.*)

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Torsten
Torsten el 21 de Mayo de 2021
Editada: Torsten el 22 de Mayo de 2021
function main
p=0.1:0.5:10;
gss0 = 1.0;
for i=1:numel(p)
gss(i)= fzero(@(x)fun(x,p(i)),gss0)
gss0 = gss(i);
end
plot(p,gss)
end
function gssres = fun(gss,p)
m = 4.7542;
gsms = 12.684;
m1 = m - gss;
k = (3*p*pi^2 / 2)^(1/3);
k1 = sqrt(k^2+m1^2);
F = gsms*m1*( k1-m1^2/2*log((k1+k)/m1) )/pi^2 - gss
gssres = F ;
end
Maybe you will have to change gss0 = 1.0 (a guess for gss for p=0.1) to make the program start.

Más respuestas (1)

Mike Mierlo van
Mike Mierlo van el 21 de Mayo de 2021
Please specify variable: 'gss'. This one is unknown in your function.
Also what Tayyab says: what do you want to solve?
It helps a lot if you comment with % after each line what the variable means.

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