While loop and randomization

Thank you in advance for your help!

if (valCount == ones)
    disp(y1)
else
    disp('repetition')
end 
% this if/end works manually, but it's not a while loop, so it doesn't work
% automatically... 

[Jan]

Unfortuantely you have removed important parts of your question. Please don't do this. The nature of this forum is sharing problems and solution. The voluntary users spend time to help you and they want the thread to be useful for others also.

Answer 1

[Jan]

x = [1 1 1 2 2 2 3 3 3];

ready = false;
while ~ready
   y1 = [x(randperm(numel(x))); x(randperm(numel(x))); x(randperm(numel(x)))];
   ready = numel(unique(y1(:, 1))) == size(y1, 1);
end

Instead of a rejection you can use an constructive method:

x    = [1 1 1 2 2 2 3 3 3];
nx   = numel(x);
ux   = unique(x);
nRow = 3;
y1   = zeros(nRow, nx);
for k = 1:nRow
   v = x(randperm(nx));
   v(find(v == ux(k), 1)) = [];
   y1(k, :) = [ux(k), v];
end

[Marie Marie]

thank you!