# How to find the 12th highest value for every year

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Nicky Benedict el 7 de Jun. de 2021
Respondida: Nicky Benedict el 9 de Jun. de 2021
I have a data set that I have made into a table and used the sort funtion to make it into descending order based on the year followed by the 2nd column values i.e.
2014 3.98 10.34
2014 3.93 10.24
2014 3.90 10.18
.
.
.
2006 0.61 5.05
2006 0.54 5.01
2006 0.52 4.98
2006 0.50 4.89
2006 0.50 4.79
I want to find the 12th highest value for each year (the 12th row for every year).
The number of data measurements for each year are not equal. For example, in year 2014 there might be 12000 rows but in year 2010 there may only be 11500 rows of data
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Nicky Benedict el 9 de Jun. de 2021
I figured it out.
T_sort = sortrows(T,[1,2,3],'descend');
[yr,index] = unique(T_sort.Years);
index_new = index + 11;
hour_12 = T_sort(index_new,:);
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### Más respuestas (1)

SALAH ALRABEEI el 7 de Jun. de 2021
Since you already sorted them, what you need to do now is call the first highest 12 as follows
% Assuming the matrix is A where the 1st col is the years.
B = [];
years = unique(A(:,1));
for i = 1: length(years)
B= [B,(A(A(:,1)==years(i),12))];
end
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SALAH ALRABEEI el 9 de Jun. de 2021
Sorry that was my mistake. Please add replace this wth what is inside the loop
%
btemp = A(A(:,1)==years(i),:);
B = [B ; btemp(12,:) ];
Nicky Benedict el 9 de Jun. de 2021
The approach you took ended up just giving me the years but I managed to figure it out with the help of the "unique" function you had in your code. Thank you for all your help. I appreciate it. I posted my code down below if you want to know what I did.

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