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min function on two arrays

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Robert Demyanovich
Robert Demyanovich el 8 de Jun. de 2021
Comentada: Walter Roberson el 8 de Jun. de 2021
I've read the documentation on the min function, but still don't understand how it works on two arrays. I have the following:
dS=zeros(1,N)
dS=min(cA(i+1,:),cB(i+1,:))
where cA and cB are equally sized arrays. Doesn't the min function just take the value at equivalent locations in cA or cB that is the lowest. So if position 10,50 in cA is 5 and the same position in cB is 3, min returns 3 in the resulting row vector, dS, at column 50. Is that correct?
  3 comentarios
Robert Demyanovich
Robert Demyanovich el 8 de Jun. de 2021
No, I'm just a MatLab beginner trying to understand some complex (for me, anyway) code.
What if dS had been defined as an array? I guess the result is the same because in both cA and cB, the i+1 row has been specified.
James Tursa
James Tursa el 8 de Jun. de 2021
Editada: James Tursa el 8 de Jun. de 2021
This line creates dS as a vector:
dS=zeros(1,N)
Then this line completely overwrites the dS you just created and instead assigns dS the result of the min( ) function call:
dS=min(cA(i+1,:),cB(i+1,:))
I.e., the first line is completely useless and accomplishes nothing because it gets overwritten in the second line.
And yes, cA(i:1,:) and cB(i+1,:) will be a row vectors if i is a scalar.

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SALAH ALRABEEI
SALAH ALRABEEI el 8 de Jun. de 2021
%
dS=min([cA(i+1,:),cB(i+1,:)])
  3 comentarios
SALAH ALRABEEI
SALAH ALRABEEI el 8 de Jun. de 2021
Oops, yes it must be semicol; Thanks.
% correction
dS=min([cA(i+1,:);cB(i+1,:)])
Walter Roberson
Walter Roberson el 8 de Jun. de 2021
That would work in the case that cA and cB have the same number of columns.
The original code
dS=min(cA(i+1,:),cB(i+1,:))
would also work if one of cA or cB had a single column and the other one did not.

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