Subtract 1 from variable each second

Imagine I got something like this:
counter = 100;
while true
do_something=true;
pause(rand);
disp(counter);
end
Then I need the counter variable to get subtracted by 1 each second inside the while loop. Any suggestions?

 Respuesta aceptada

Jan
Jan el 10 de Jun. de 2021
counter = 100;
TimerH = timer('TimerFcn', @doCount, 'ExecutionMode', 'fixedRate', ...
'Period', 1.0, 'UserData', counter);
start(TimerH);
while true
do_something=true;
pause(rand);
counter = TimerH.UserData;
disp(counter);
end
delete(TimerH);
function doCount(TimerH, EventData)
TimerH.UserData = TimerH.UserData - 1;
end
Do you really need an active counter?
iniTime = clock;
while true
do_something=true;
pause(rand);
counter = 100 - etime(clock, iniTime);
disp(counter);
end

3 comentarios

Mathieu NOE
Mathieu NOE el 10 de Jun. de 2021
Whow
I'm impressed !
so much science for a counter !
Martin
Martin el 10 de Jun. de 2021
me2, thanks!
Jan
Jan el 10 de Jun. de 2021
@Mathieu NOE: And it even counts backwards from 100 for 3 weeks. :-)

Iniciar sesión para comentar.

Más respuestas (1)

Mathieu NOE
Mathieu NOE el 10 de Jun. de 2021
hi
nothing fancy
counter = 100;
while true
do_something=true;
counter = counter -1; % decrement counter
pause(1); % 1 second pause
disp(counter);
end

3 comentarios

Martin
Martin el 10 de Jun. de 2021
Editada: Martin el 10 de Jun. de 2021
yeah I know this one, but the hing is pause has to be pause(rand); (this loop can take between something like 0.001sec and 3 weeks)...
Mathieu NOE
Mathieu NOE el 10 de Jun. de 2021
so how do you plan to get the counter decremented every second ??
Martin
Martin el 10 de Jun. de 2021
Editada: Martin el 10 de Jun. de 2021
yeah thats my question :) I guess I need to use
now
(before the loop) and also indside the loop, but I have hard times figure it out which is why I am asking

Iniciar sesión para comentar.

Categorías

Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

Productos

Versión

R2020b

Preguntada:

el 10 de Jun. de 2021

Comentada:

Jan
el 10 de Jun. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by