defining a function output properly

Hi guys! I have a problem in properly defining my output in a function.

According to n= max(position{:,4}); I have different T1, T2,..Tn as arrays.

But how to define all of these in my function output if I do not know in advance how many of them I will have?

[T,n] = paramdisp(position)

Doing so it does not work.

Thanks. I'm new to matlab.

Answer 1

[Steven Lord]

So you want to call a function that can return different numbers of outputs and you want to get a number of outputs that is only known when the code is run not when it is written?

Can you define variables with numbered names like X1, X2, X3, ... ? Yes.

Should you do this? Generally we recommend against it.

Instead I recommend building a cell array and using a comma-separated list.

% Sample data
A = magic(5);

% Preallocate the cell to hold the desired number of outputs
numOutputs = 2;
theOutputs = cell(1, numOutputs);

% Fill in the cell
[theOutputs{:}] = svd(A);

% Call the function with the same number of outputs specified explicitly
% when the code is written so we can compare to the comma-separed list
[output1, output2] = svd(A);

% Compare the two approaches
isequal(theOutputs{1}, output1)

ans = logical
   1

isequal(theOutputs{2}, output2)

ans = logical
   1

If you wanted to call svd with three outputs using the theOutputs cell array the only thing you'd need to change is the line that defines the numOutputs variable.

[Riccardo Tronconi]

Thanks for your comment! Just to try, is it possible to use the same approach with arrays?

[Stephen23]

"...is it possible to use the same approach with arrays?"

A cell array already contains arrays. Every array in a cell of a cell array is itself an array.