Error using Contour: input arguments must be numeric or objects which can be converted to a double

Hi, I have the given code where I try to plot levels curves of the givenfunction
syms r x y k z
[ph,r] = meshgrid((0:5:360)*pi/180,0:.5:10);
[X,Y] = pol2cart(ph,r);
Z = X+i*Y;
J = besselj(k,l.*r);
J2 = besselj(k,m.*r);
Y = bessely(k,l.*r);
Y2 = bessely(k,m.*r);
H = besselh(k,r);
F1 = symsum((J).*exp(1i*k*ph),k,-5,5);
F2 = symsum((J2+Y2).*exp(1i.*k.*ph),k,-5,5);
F3 = symsum(H.*exp(1i.*k.*ph),k,-5,5);
pwu = nan(size(F1), 'like', F1);
mask = 0 <= r & r < 0.5;
pwu(mask) = F1(mask);
mask = 0.5 <= r & r < 1;
pwu(mask) = F2(mask);
mask = r >= 1;
pwu(mask) = F3(mask);
U = subs(pwu, {l, m}, {1.5, 3});hold on
contour(X,Y,imag(double(U)),30)
axis equal
xlabel('r','FontSize',14);
ylabel('phi','FontSize',14);
But I get an error for the 4th last line. How can this be made in a way it is converted to a double?
Thanks!

1 comentario

I'm not able to run this script because the variables l, m, n, etc are not defined. Could you update the attached code so that your error can be reproduced?

Iniciar sesión para comentar.

 Respuesta aceptada

Yes, here it is, working script
syms r x y k z l m
[ph,r] = meshgrid((0:5:360)*pi/180,0:.5:10);
[x,y] = pol2cart(ph,r);
Z = x+1i*y;
J = 0.9426656*besselj(k,l.*r);
J2 = 0.640840882*besselj(k,m.*r);
Y = bessely(k,l.*r);
Y2 = 0.4361500838*bessely(k,m.*r);
H = 1.1159118143*besselh(k,r);
F1 = symsum((J).*exp(1i*k*ph),k,-5,5);
F2 = symsum((J2+Y2).*exp(1i.*k.*ph),k,-5,5);
F3 = symsum(H.*exp(1i.*k.*ph),k,-5,5);
pwu = nan(size(F1), 'like', F1);
mask = 0 <= r & r < 0.5;
pwu(mask) = F1(mask);
mask = 0.5 <= r & r < 1;
pwu(mask) = F2(mask);
mask = r >= 1;
pwu(mask) = F3(mask);
U = subs(pwu, {l, m}, {1.5, 3});hold on
w=double(U)
contour(x, y, angle(double(U)), 30);
axis equal
xlabel('r','FontSize',14);
ylabel('phi','FontSize',14);

Más respuestas (0)

Categorías

Más información sobre Contour Plots en Centro de ayuda y File Exchange.

Productos

Versión

R2021a

Etiquetas

Preguntada:

el 22 de Jun. de 2021

Respondida:

el 24 de Jun. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by