How to find first instance of a value in array?
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Tawsif Mostafiz
el 4 de Jul. de 2021
Comentada: Tawsif Mostafiz
el 5 de Jul. de 2021
Hi, I am writing a code that as follows:
arr(p)=abs(c); %absolute value of c
if(arr(p)<1)
if(arr(p)>0.9)
array(t)=white1;
cor(t)=arr(p); %correlation for c>.95 && c<1
t=t+1;
end
end
maximum=max(cor); %maximum value of cor(t)
Now, I am trying to find the first instance the value of maximum comes in the "arr" Array.
I have tried the following:
1.
for v=1:x
if(maximum==arr(v))
% x=find(arr==maximum);
u=u+1;
if(u==1) %making sure only the first max value is taken
q=value(v); %q is becoming always 0.5,have to fix it
end
end
end
and,
2.
x=find(arr==maximum);
and,
3.
x = find(maximum == arr,'first') ;
In the 1st and 2nd try, when I use fprintf to detect the x, it prints blank, such as,
"x is "
In the 3rd try the following error occurs,
Second argument must be a positive scalar integer.
How can I fix it?
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Respuesta aceptada
Steven Lord
el 4 de Jul. de 2021
You could use logical indexing.
rng('default')
c = randn(1, 10)
arr = abs(c)
% Overwrite those values in arr that are out of bounds with NaN. I'm using
% wider bounds to show the technique with a small data set.
arr(arr > 1.5) = NaN
arr(arr < 0.5) = NaN
[value, location] = max(arr, [], 'omitnan')
If all you're interested in is the value and not its location in c you could delete the elements of arr that fall out of bounds.
arr2 = abs(c);
arr2(arr2 > 1.5) = [];
arr2(arr2 < 0.5) = []
[value2, location2] = max(arr2)
location2 is not the same as location because arr2 does not have the same number of elements as either arr or c.
Más respuestas (2)
Jiro Doke
el 4 de Jul. de 2021
Is this what you're looking for?
maximum = 5;
arr = [2 4 3 5 7 3 4];
find(arr == maximum, 1)
1 comentario
Tawsif Mostafiz
el 4 de Jul. de 2021
Editada: Tawsif Mostafiz
el 4 de Jul. de 2021
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