for recursive formula index value

I was coding the formual
The summation runs for l=0 to k
I write the following code :
syms x
syms a
T=zeros(1,10,'sym')
T(1)=a;
T(2)=0;
for k=2:10
if k==2
A=1
for i=1:k
T(k+2-i)=(-A-(k+2-i)*(k+1-i)*T(k+2-i))/((k-i+1)*(k-i+2));
end
else
A=0
end
end
disp(T)
Here my code is: Now I have asumr T(2) as 0 but when it display T it is showing 2.

Respuestas (1)

Prince Kumar
Prince Kumar el 13 de Ag. de 2021
From my understanding T(2) is getting updated after running the program but you have assumed T(2) to be 2 at the staring of the program.This might be because in this line
for i=1:k
T(k+2-i)=(-A-(k+2-i)*(k+1-i)*T(k+2-i))/((k-i+1)*(k-i+2));
end
you are changing T(2) for i=2 and k=2.
Hence T(2) is getting updated from 0 to some other value.

Etiquetas

Preguntada:

el 13 de Jul. de 2021

Respondida:

el 13 de Ag. de 2021

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