Fmincon solution is same as initial guess

Hello,
My Fmincon function does not minimize the cost function, instead, it reports the same initial guess provided to it. Please help with recommendations to the piece of code below:
function J=cost_function(y)
for i=1:size(a,1)
AA = y0*b(i,:)';
BB = y0*c(i,:)';
CC = (y0(1).*c(i,1)/BB)*c(i,1) + (y0(2).*c(i,2)/BB)*c(i,2);
DD = y0*d(i,:)';
EE = y0*e(i,:)';
all(i,:)=[AA, BB, CC, DD, EE];
end
J=sum(abs(all(1,:) - x(1:5)') ./ x(1:5)')^2;
The script calculates the a, b, c, d, e,....... and passes them to the function along with "y0".
Please advise, and thanks in advance

 Respuesta aceptada

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 14 de Jul. de 2021
Editada: Sulaymon Eshkabilov el 14 de Jul. de 2021
THere are a couple of errs oin your fcn, i.e. y0, a,b,c,d not defined. Moreover, x is not defined.
function J=cost_function(y0, a, b, c, d, e, x)
for i=1:size(a,1)
AA = y0*b(i,:)';
BB = y0*c(i,:)';
CC = (y0(1).*c(i,1)/BB)*c(i,1) + (y0(2).*c(i,2)/BB)*c(i,2); % Check: multiplied and divided by c(i,1) and c(i,2)
DD = y0*d(i,:)';
EE = y0*e(i,:)';
all(i,:)=[AA, BB, CC, DD, EE];
end
J=sum(abs(all(1,:) - x(1:5)') ./ x(1:5)')^2;

4 comentarios

Samy Alkhayat
Samy Alkhayat el 14 de Jul. de 2021
All of these are defined in the script that calls the function. Should they be defined inside the function?
Sulaymon Eshkabilov
Sulaymon Eshkabilov el 14 de Jul. de 2021
yes.
Samy Alkhayat
Samy Alkhayat el 14 de Jul. de 2021
Thank you very much.
Sulaymon Eshkabilov
Sulaymon Eshkabilov el 15 de Jul. de 2021
Most welcome!

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Design, Analysis, Benchmarking, and Verification en Centro de ayuda y File Exchange.

Productos

Versión

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by