a loop that checks for missing decimals in a vector, but it only runs once

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if want it to remove the numbers if it doesnt have 1.1, 1.2, 1.3 and so on up til 5 but it only runs once
v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
length(y)
for i = length(v)
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
length(y)
if length(y) < 3
v(y)=[];
c = c+1;
else
c = c+1;
end
end
  1 Comment
Rik
Rik on 5 Aug 2021
What are you actually trying to do? Your code is uncommented and your single line description is not clear to me.

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Answers (1)

Awais Saeed
Awais Saeed on 5 Aug 2021
I think you want to delete elemetns of vector c from vector v. If that is what you want then you can do it as shown below
v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
for col = length(y):-1:1 % You must do this in reverse order as the size of vector v will keep changing
idx = y(col);
v(idx) = [];
end
  2 Comments
Mads Albertsen
Mads Albertsen on 11 Aug 2021
i figured it out, was just missing i = 1:length(v) since i need c to check for all the numbers uptil 5, so 4.2 also is removed since it is missing 4.1 and/or 4.3, sorry for being unclear

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