Convert a matrix to { }

9 visualizaciones (últimos 30 días)
Martin Park
Martin Park el 6 de Oct. de 2013
Editada: Andrei Bobrov el 7 de Oct. de 2013
Can anyone help me to convert a matrix that is for instance:
0 1 2
3 4 5
6 7 8
called symbols obtained from an image to something that is in the following form symbols= {'0' '1' '2' '3' '4' '5' '6' '7' '8'}.

Respuestas (3)

Jan
Jan el 6 de Oct. de 2013
Editada: Jan el 6 de Oct. de 2013
symbols = [0 1 2; ...
3 4 5; ...
6 7 8];
S = sprintf('%g*', symbols.');
S(end) = []; % Remove trailing *
C = regexp(S, '*', 'split');
Another simpler method:
C = cell(1, numel(symbols));
symbols = symbols.';
for iC = 1:numel(symbols)
C{iC} = sprintf('%g', symbols(iC));
end
I'm not convinced, that the conversion will really help to solve your problem.

Jan
Jan el 6 de Oct. de 2013
Or:
symbols = [0 1 2; 3 4 5; 6 7 8];
C = num2cell(char('0' + symbols.'))
  1 comentario
Jan
Jan el 6 de Oct. de 2013
This fails when any element of the input is outside [0, 9].

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Andrei Bobrov
Andrei Bobrov el 6 de Oct. de 2013
Editada: Andrei Bobrov el 7 de Oct. de 2013
A = [0 1 2
3 4 5
6 7 8];
cellstr(sprintf('%d',A')')'
other variant:
regexp(num2str(reshape(A.',1,[])),'\d*','match')
  2 comentarios
Jan
Jan el 6 de Oct. de 2013
Editada: Jan el 6 de Oct. de 2013
This fails when any element of the input is outside [0, 9].
Andrei Bobrov
Andrei Bobrov el 7 de Oct. de 2013
Editada: Andrei Bobrov el 7 de Oct. de 2013
Hi Jan, I agree with you and I suggest another option.

Iniciar sesión para comentar.

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