how to normalize a uniformly distributed random values such that every row sum of X(:,:,i) should be 1 except for ith row?
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chan
el 16 de Ag. de 2021
Comentada: Walter Roberson
el 29 de Sept. de 2021
X = rand([6,3,6]);
how to normalize a uniformly distributed random values such that every row sum of X(:,:,i) should be 1 except for ith row?
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Walter Roberson
el 16 de Ag. de 2021
X = rand([6,3,6]);
Xn = X ./ sum(X,2);
for i = 1 : min(size(X,1),size(X,3))
Xn(i,:,i) = X(i,:,i);
end
Could it be done without a loop? Probably. Is it worth doing without a loop? That is not clear.
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Walter Roberson
el 29 de Sept. de 2021
i need every row sum of X(:,:,i) should be 1 except for ith row.
The code already does that. sum(Xn(:,:,1),2) is all 1 except for row 1, sum(Xn(:,:,2),2) is all 1 except for row 2.
This ith row should come from user's choice.
What does the user's choice have to do with it?
Your requirements are that all rows should sum to 1 except X(1,:,1), X(2,:,2), X(3,:,3), X(4,:,4)
if i=3 then all rows should be one except the row 3 in all the matrices...
No, that contradicts your earlier requirements that every row sum of X(:,:,i) should be 1 except for ith row. In the case of i = 3, your requirement is that every row sum of X(:,:,3) should be 1 except for row 3, X(3,:,3) not that the sum should be 1 except for row 3 in all of the matrices, such as X(3,:,2) .
If you had asked for every row sum of X(:,:,:) to be 1 except for row i, i chosen by the user, then that would be a different matter.
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