Why does poly() not evalp

1 visualización (últimos 30 días)
Billy
Billy el 14 de Jun. de 2011
I have an example:
evalp( poly( sqrt( 1-x^2 ), [x] ), x=cos(0.5) )
This gives (sqrt(1-x^2)) as the response.
The expected result is only given by
evalp( poly( sqrt( 1-x^2 ), [x] ), x=cos(0.5) ) | x=cos(0.5)
And evalp works as expected with simple expression like
evalp( poly( x, [x] ), x = 1 )
Is this a bug?

Respuesta aceptada

Walter Roberson
Walter Roberson el 15 de Jun. de 2011
sqrt( 1-x^2 ) is not a polynomial. evalp() is only for evaluating polynomials.
I am not familiar with the way you used "|" in your second expression. I looked through the Standard Library but I do not find any meaning defined for "|" . Could you give a reference on that?
  4 comentarios
Billy
Billy el 15 de Jun. de 2011
I'm using poly() to simulate the output of my P function I just wrote, which outputs a poly() (in turn because orthpoly::legendre outputs a poly).
Ultimately I'm trying to evaluate the legendre polynomials with cos(t) in the place of x in legendre(n,x).
Billy
Billy el 15 de Jun. de 2011
The P function is here: http://www.mathworks.com/matlabcentral/answers/9485-how-do-i-specify-m-for-orthpoly-legendre

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre MuPAD en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by