similar matrix multiplication speed up

Hi,
I need to multiply many times matrices of the same type. Is there a way to speed this up:
M1^m*M2^m*...
where Mi = expm(alpha(i)*P) P being a matrix (hermitian). Already all Mi are precalculated and the main calculation cost of my problem now is the long matrix multiplication through all i.
Thanks

Más respuestas (3)

Gary
Gary el 20 de Jun. de 2011

0 votos

mtimesx might help to calculate the Mi matrices and its power but can it speed up the multiplication between Mi?
Thanks for the answer btw.

1 comentario

Paulo Silva
Paulo Silva el 20 de Jun. de 2011
Sorry but I can't help further, never used it.

Iniciar sesión para comentar.

Teja Muppirala
Teja Muppirala el 20 de Jun. de 2011
You can combine all of those multiplications into one expression using the properties of the matrix exponential.
Compare these 3 expressions:
P = rand(3);
P = P*P';
format long
% These are all the same
expm(2*P)^7*expm(4*P)^7*expm(5*P)^7
expm(14*P)*expm(28*P)*expm(35*P)
expm(7*(2+4+5)*P)
Gary
Gary el 20 de Jun. de 2011

0 votos

Sorry the expression given at the beginning was kind of stupid. The Mi matrices are of the form Mi=expm(P0+alpha(i)P1) where P0 and P1 are hermitian and most of all non commutative. I cannot combine the terms.

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el 20 de Jun. de 2011

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