Problem 42935. Sums of cubes and squares of sums
Given the positive integers 1:n, can you:
1. Compute twice the sum of the cubes of those numbers. 2. Subtract the square of the sum of those numbers. 3. Divide that result by n/2.
So, for n = 3, we might compute a result like this:
((1^3 + 2^3 + 3^3)*2 - (1 + 2 + 3)^2)/(3/2) ans = 24
Yes, you probably can do all of this, but be careful on this problem, as n may be somewhat large, and I am expecting to see the correct result, not just an approximate value. Remember there are always different ways one may solve a problem.
I point out the Project Euler reference because PE problem 6 is what made me think of this problem, and because the test cases will push the limits of what you can do if you are not careful.
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