Too bad this problem number has a '5' in it! :-)
Ha Ha! six is the new 5!
Any suggestions on my brute force method?
sorry, I added a couple of test cases to discourage this sort of solutions
Right and wrong
Bottles of beer
Given a window, how many subsets of a vector sum positive
Get the elements of diagonal and antidiagonal for any m-by-n matrix
Knave in the middle attack
Say something funny
singularity 2.0 (really hard)
Knights and Knaves (part 2)
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