Create n x 2n "mirror" matrix of this type:
For n = 2
m = [ 1 2 2 1
1 2 2 1 ]
For n = 3
m = [ 1 2 3 3 2 1
1 2 3 3 2 1
1 2 3 3 2 1 ]
This problem was fun. I was able to find a better way to solve beat my own solution. Not the best way though. But lot better.
Find the peak 3n+1 sequence value
Arrange vector in ascending order
Are all the three given point in the same line?
Find the logic
frame of the matrix
Sum of series II
Sum of series VI
Sum of series V
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