Number of rows based on frequency of one integer and position of another integer

1 visualización (últimos 30 días)
Hello. I was wondering if someone could help me with this:
Let's say you have a 2000 x 2 matrix, where all the elements are integers. How can we count the number of rows that contain the number 10 in its first column and any number with the highest 5 integers in the second column?
In other words, the following but where X is the fifth highest number in the second column:
nnz(matrix(:,1) == 10 & matrix(:,2) > X);
EDIT -> Very importantly, the list with the highest 5 integers must be determined for each integer in the first column. So, if one wanted to do this for the number 10, it must be determining the highest 5 integers in the second column WHEN the integer in the first column is 10.
Thanks!

Respuesta aceptada

Voss
Voss el 17 de En. de 2022
Get the set of unique numbers in the 2nd column:
col2_vals = unique(matrix(:,2));
The 5th highest is 4th from the end. So, to match any number within the highest 5:
nnz(matrix(:,1) == 10 & matrix(:,2) >= col2_vals(end-4));
  4 comentarios
Voss
Voss el 18 de En. de 2022
idx = matrix(:,1) == 10;
col2_vals = unique(matrix(idx,2)); % now: unique values of column 2 where column 1 is 10
nnz(matrix(idx,2) >= col2_vals(end-4));

Iniciar sesión para comentar.

Más respuestas (1)

David Hill
David Hill el 17 de En. de 2022
r=unique(matrix(:,2));
r=r(end-4:end);
n=nnz(matrix(:,1)==10&ismember(matrix(:,2),r));
  3 comentarios
David Hill
David Hill el 18 de En. de 2022
r=unique(matrix(matrix(:,1)==10,2));
r=r(end-4:end);
n=nnz(matrix(:,1)==10&ismember(matrix(:,2),r));
Neuro
Neuro el 18 de En. de 2022
Thanks @David Hill, but it gives me an error message:
Error using unique (line 117)
Invalid input. Valid flags are 'rows', 'first', 'last', 'stable', 'sorted', 'legacy'.

Iniciar sesión para comentar.

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by