function [X_norm, mu, sigma] = featureNormalize(x)
%FEATURENORMALIZE Normalizes the features in X
% FEATURENORMALIZE(X) returns a normalized version of X where
% the mean value of each feature is 0 and the standard deviation
% is 1. This is often a good preprocessing step to do when
% working with learning algorithms.
% You need to set these values correctly
X_norm= x;
mu = zeros(1, size(x, 2));
sigma = zeros(1, size(x, 2));
% ====================== YOUR CODE HERE ======================
% Instructions: First, for each feature dimension, compute the mean
% of the feature and subtract it from the dataset,
% storing the mean value in mu. Next, compute the
% standard deviation of each feature and divide
% each feature by it's standard deviation, storing
% the standard deviation in sigma.
%
% Note that X is a matrix where each column is a
% feature and each row is an example. You need
% to perform the normalization separately for
% each feature.
%
% Hint: You might find the 'mean' and 'std' functions useful.
%
for l=1:size(x,2)
mu=mean(x(:,l));
sigma=std(x(:,l));
X_norm=(x(:, l) - mu)./sigma;
end

3 comentarios

KSSV
KSSV el 28 de Feb. de 2022
What is the error? You have not speciffied the error.
Zoha Yaghmayi Benis
Zoha Yaghmayi Benis el 28 de Feb. de 2022
Not enough input arguments.
Error in featureNormalize (line 9)
X_norm= x;
Stephen23
Stephen23 el 28 de Feb. de 2022
@Zoha Yaghmayi Benis: did you define the input x when you called the function?

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Respuestas (1)

David Hill
David Hill el 28 de Feb. de 2022

0 votos

for l=1:size(x,2)
mu(l)=mean(x(:,l));
sigma(l)=std(x(:,l));
end
X_norm=(x-mu)./sigma;
Alternatively, no for-loop is needed.
mu=mean(x);
sigma=std(x);
X_norm=(x-mu)./sigma;

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