Split an array using specific points
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Daniel Adeniyi
el 1 de Mzo. de 2022
Comentada: Stephen23
el 26 de Abr. de 2022
Just starting out in matlab and would appreciate your help.
for example : lets say I have an array Y = [5;2;3;6;7;9;5;5;6;3;8;7;74;9;63;47;10;3]; and another array of index diiv = [5;9;15];
How can i use diiv to break Y into smaller arrays so I would get as output arrays y1 = [5;2;3;6;7], y2 =[9;5;5;6]; y3 =[3;8;7;74;9;63]; y4=[47;10;3]
Thanks
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Stephen23
el 2 de Mzo. de 2022
Editada: Stephen23
el 2 de Mzo. de 2022
If you are numbering your variables like that then you are doing something wrong.
If you are trying to access variable names dynamically then you are doing something wrong.
Simple and efficient MATLAB code uses arrays and indexing. You should use arrays and indexing.
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Stephen23
el 2 de Mzo. de 2022
Editada: Stephen23
el 2 de Mzo. de 2022
Simpler and more efficient than what you are attempting (although most likely you don't realise that yet):
Y = [5;2;3;6;7;9;5;5;6;3;8;7;74;9;63;47;10;3];
diiv = [5;9;15];
D = diff([0;diiv;numel(Y)]); % complete the missing data
C = mat2cell(Y,D,1) % split into a cell array
C{:}
Más respuestas (2)
Alan Stevens
el 1 de Mzo. de 2022
Like this?
Y = [5;2;3;6;7;9;5;5;6;3;8;7;74;9;63;47;10;3];
diiv = [5; 9; 15];
y1 = Y(1:diiv(1));
y2 = Y(diiv(1)+1:diiv(2));
y3 = Y(diiv(2)+1:diiv(3));
y4 = Y(diiv(3)+1:end);
2 comentarios
Stephen23
el 2 de Mzo. de 2022
Editada: Stephen23
el 2 de Mzo. de 2022
"is it possible to do this automatically (like in a loop) without writing out each expression for y1, y2,y3,y4"
It is certainly possible, but only if you want to force yourself into writing slow, complex, inefficient code which is buggy and hard to debug:
In contrast the neat, simple, and very efficient MATLAB approach is to use indexing.
Tip: if you are numbering your varaible names like that, then you are doing something wrong.
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