Adressing

Hello, If i have:

   A=[1 2 3 ;7 5 3;9 8 3;11 53 45]

   A =

     1     2     3
     7     5     3
     9     8     3
    11    53    45

and i do

>> A(9)

ans =

     3

How can i know the row and coloumn through its index value ???

Thanks

Answer 1

[Fangjun Jiang]

help sub2ind
help ind2sub

[row,col]=ind2sub(size(A),9)

I guess you mean this:

A=[1 2 3 ;7 5 3;9 8 3;11 53 45];
[Row,Col]=find(A==9)

[developer]

its not working :(

[Fangjun Jiang]

What do you mean? You can't run this?

A=magic(3);[row,col]=ind2sub(size(A),9)

[Fangjun Jiang]

Okay, I see! See update.