Moving Decimal Places to the right
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Joydeb Saha
el 29 de Sept. de 2022
Comentada: Jan
el 29 de Sept. de 2022
How can I get the number format as 1412701202.018284 for an exponent format data 1.412701202025964e+09. May be with sprintf "%.6f" or equivalent ? I need to do the task for a mat file I am attaching.
2 comentarios
Jan
el 29 de Sept. de 2022
The number format matters for the text output only. In a comment above you mention, that you want to get a double as output. This is not meaningful. So which problem do you want to solve actually?
Rik
el 29 de Sept. de 2022
@Joydeb Saha You need to first respond to the question Jan raised: what is it you want? Do you want a char or a double as the output? In the first case you need sprintf, in the second case your question does not make sense, as that is just how the data is displayed, not the underlying data itself.
What exactly do you want to achieve?
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VBBV
el 29 de Sept. de 2022
Editada: VBBV
el 29 de Sept. de 2022
format long % format long option
sprintf('%6f',1.412701202025964e+09)
9 comentarios
Jan
el 29 de Sept. de 2022
@Joydeb Saha: As said already, you can store the array in the shown format as CHAR array only:
S = sprintf('%6f\n', GTt)
If you want to store it numerically, the format has no meaning. Matlab stores value in the IEEE754 format and you cannot incfluence the location of the decimal point.
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