how to save the values of DelL(T)

Lo = 44.46

Do = 18.76

alpha = 0.0002178

for T = 36:1:180

DeltaL = Lo*alpha*(T-35)

DelL(T) = DeltaL

end

I need the T value going from 36 through 180 and store the values in array

Answer 1

[Chunru]

Lo = 44.46; 
Do = 18.76; 
alpha = 0.0002178 ;

T = 36:1:180;
DelL = Lo*alpha*(T-35);

whos

  Name        Size             Bytes  Class     Attributes

  DelL        1x145             1160  double              
  Do          1x1                  8  double              
  Lo          1x1                  8  double              
  T           1x145             1160  double              
  alpha       1x1                  8  double              
  cmdout      1x33                66  char                

Answer 2

[VBBV]

Lo = 44.46 

Lo = 44.4600

Do = 18.76 

Do = 18.7600

alpha = 0.0002178 

alpha = 2.1780e-04

for T = 36:1:180
DeltaL = Lo*alpha*(T-35);
DelL(T) = DeltaL;
end
 
DelL(DelL == 0) = []  % use this to delete zeros in DelL matrix 

DelL = 1×145

0.0097 0.0194 0.0291 0.0387 0.0484 0.0581 0.0678 0.0775 0.0872 0.0968 0.1065 0.1162 0.1259 0.1356 0.1453 0.1549 0.1646 0.1743 0.1840 0.1937 0.2034 0.2130 0.2227 0.2324 0.2421 0.2518 0.2615 0.2711 0.2808 0.2905

[VBBV]

Matlab creates vector of zeros preceding the array formed using for loop. In your case, it is DelL array

[VBBV]

Alternately, you can do it much simpler way without for loop as suggested by @Chunru.