Random pulse generator
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Néstor Monedero
el 19 de Oct. de 2011
Comentada: sneha j
el 3 de Mayo de 2021
Hello,
I'm new in Simulink and i trying to make a pulse random generator. Pulses have amplitude (+10 & -10) and width (1 ms). The signal has to be non periodic, i mean, pulses has to appear by a random series. how can i do it? I apprecitate any help. The begining of my project depend of this signal.
Thanks. Néstor.
3 comentarios
Azzi Abdelmalek
el 29 de Oct. de 2012
Check the second image (modified)
set the Amplitude of the pulse generator to 2 and substract 1
Respuesta aceptada
Azzi Abdelmalek
el 27 de Oct. de 2012
Editada: Azzi Abdelmalek
el 27 de Oct. de 2012
use this block
the function is
function y = fcn(u)
%#codegen
id=rand(1)
if id>0.5 & u==0
y=1
else
y=0
end
or easier
%
0 comentarios
Más respuestas (2)
Fangjun Jiang
el 19 de Oct. de 2011
Go to Simulink Sources library, there is the Random Number block and the Uniform Random Number block.
The output of the Uniform Random Number is between 0 and 1, so you'll need to use Relational Operator block to compare it with constant such as 0.1 and 0.9, and then use Switch block to output the +10 or -10 or 0 pulse value.
3 comentarios
Fangjun Jiang
el 21 de Oct. de 2011
You can compare the random number with a constant, e.g. 0.9 and then add a zero-order holder block.
Néstor Monedero
el 28 de Nov. de 2011
2 comentarios
sneha j
el 3 de Mayo de 2021
hi, there is a bug in ur code.
In the case that u(i)<-0.9, y(i) sets to -1 in the first if-block.
But wen it executes the 2nd if-block - if gets overwritten by y(i)=0 as u(i)<0.9, so it executes the else part of the block.
U need to club the the first if block with the 2nd if-else block into one if block as follows:
if(u(i)<-0.9)
y(i)=-1;
else if(u(i)>0.9)
y(i)=1;
else
y(i)=0;
end
Hope it works well.
sneha j
el 3 de Mayo de 2021
hi Nestor, sorry i jus realised that the else if block doesnt work, so here is a workaround:
if(u<-0.5)
y=-10;
else
y=0;
end
if(u>0.5)
y=10;
end
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