Borrar filtros
Borrar filtros

how to do loop on rows matrix?

3 visualizaciones (últimos 30 días)
Risma Fitriyani
Risma Fitriyani el 23 de Dic. de 2022
Comentada: Image Analyst el 27 de Dic. de 2022
i have zeros matrix which has 3 rows and 6 columns. i want to allocate “1” on zeros matrix for each columns in order to get the result output like this attached picture. can anyone be kind to help me? thanks in advance

Respuesta aceptada

VBBV
VBBV el 23 de Dic. de 2022
Editada: VBBV el 23 de Dic. de 2022
As mentioned in your question, if you have zeros matrix to start with and want to allocate 1s to specfiic zero locations, then you can get the matrix in snapshot using loop as below
A = zeros(3,6); % assume A as your zeros matrix
for k = 1:length(A)-2
if k == 1 | k == 2 | k == 3
A(k,k) = 1;
elseif k == 4
A(1,k) = 1;
A(2,k+1) = 1;
A(3,k+2) = 1;
end
end
A
A = 3×6
1 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 1
  2 comentarios
Risma Fitriyani
Risma Fitriyani el 23 de Dic. de 2022
Thank you for your help, it means a lot to me. Then, what if I have a matrix with a large number of rows and columns like 25x100, should I write it to A(25,k+2)? Or maybe there is a more effective way?
VBBV
VBBV el 23 de Dic. de 2022
It depends on how you want final matrix to look like. That is "in which specific positions you want to allocate 1s in zero matrix"

Iniciar sesión para comentar.

Más respuestas (2)

Markus M.
Markus M. el 23 de Dic. de 2022
Editada: Markus M. el 23 de Dic. de 2022
It looks like the 1's are only needed on the diagonal elements.
You can do this with:
repmat(eye(3),1,2)
  4 comentarios
Risma Fitriyani
Risma Fitriyani el 26 de Dic. de 2022
thank you, i’ll try this
Risma Fitriyani
Risma Fitriyani el 26 de Dic. de 2022
this is worked! thank you so much, this helped me a lot.

Iniciar sesión para comentar.


Image Analyst
Image Analyst el 26 de Dic. de 2022
Instead of a for loop, you can use the toeplitz function:
% For 3x6:
c = [1 0 0 1 0 0];
r = [1 0 0];
output = toeplitz(r, c)
output = 3×6
1 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 1
% For 15 by 25
c = [1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1];
r = [1; zeros(15, 1)];
output = toeplitz(r, c)
output = 16×25
1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1
  3 comentarios
Risma Fitriyani
Risma Fitriyani el 26 de Dic. de 2022
i want the final output would be like the attached picture above (on my question), but i have different various size matrix, that’s why i asked you how if i have size matrix 15x25 because matrix with 3x6 is only example to explain my needs
Image Analyst
Image Analyst el 27 de Dic. de 2022
@Risma Fitriyani did you not like my answer for the 15x25? Does the answer you accepted work?
Again, can you give the full output for your 15x25 matrix like @Markus M. directly asked you for? I'd like to see how my solution does not do what you want.

Iniciar sesión para comentar.

Categorías

Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.

Etiquetas

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by