Borrar filtros
Borrar filtros

Complex Transfer Function

18 visualizaciones (últimos 30 días)
John
John el 28 de Oct. de 2011
Comentada: Garba Elhassan el 15 de En. de 2022
I have searched around a little and can not work out how to enter a transfer function in the following form to Matlab:
G(s) = 1 / ( s*(s+0.5 +- 2j) )
Note that in the brackets it is "s plus 0.5 plus/minus 2 j' which is complex. Any assistance is appreciated.
  1 comentario
Garba Elhassan
Garba Elhassan el 15 de En. de 2022
Hello and Good day, I m working on a deadbeat controller with time delay in the plant. I was able to design a controller with the time delay into consideration.
my plant is :T_(d(z))=(0.26158 (z+11.81) (z+0.5335) (z+0.02728))/((z-1) (z^2- 0.2404z + 0.09597)) z^(-2) and
my controller is (0.2986z^4-0.07178z^3+0.02865z^2 )/(z^3+1.483z^2+0.5315z+0.01342)
the controller gives good response using the code.
The controller has more zeros than the poles.
now is the time to test in controller in Simulink, Transfer function block couldnot work, I try expressing the controller in partial fraction but two of the fraction has complex zeros and poles. I try using the block, expressing the controller using d-operators but I have z terms in the output equation.
I am realy confused on how to solve this issue.
your kind answers shall be highly appreciated.

Iniciar sesión para comentar.

Respuestas (1)

Fangjun Jiang
Fangjun Jiang el 28 de Oct. de 2011
Take a look at the example of
doc zpk
  2 comentarios
John
John el 29 de Oct. de 2011
Yes I see a similar example. However, I am not sure if the two are the same:
(i) - (s+0.5 +- 2j)
(ii) - (s+0.5 + 2j)(s+0.5 + 2j)
Thus I am not sure how to enter it in if (i) and (ii) are not the same?
Fangjun Jiang
Fangjun Jiang el 29 de Oct. de 2011
I don't understand your question. The point is to use zpk() to create the transfer function. For (i), it is zpk([],[-0.5+i,-0.5-i],1). For (ii), it is not a valid transfer function.

Iniciar sesión para comentar.

Categorías

Más información sobre Stability Analysis en Help Center y File Exchange.

Etiquetas

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by