Not getting the expected size matrix from evaluating a function handle that is equal to zero

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h = @(x,y) 0
[X, Y] = meshgrid(linspace(0, 2, 10));
Z = h(X,Y);
X and Y are 10 x 10.
I am expecting Z to be zeros matrix of 10x10. But I am getting Z to be a 0 of 1x1.
Why?

Respuesta aceptada

Leonardo
Leonardo el 29 de Mzo. de 2024
h = @(x,y) zeros(size(x));
[X, Y] = meshgrid(linspace(0, 2, 10));
Z = h(X,Y)
Z = 10×10
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
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surf(X,Y,Z)

Más respuestas (2)

VBBV
VBBV el 29 de Mzo. de 2024
h = @(x,y) zeros(10)
h = function_handle with value:
@(x,y)zeros(10)
[X, Y] = meshgrid(linspace(0, 2, 10));
Z = h(X,Y)
Z = 10×10
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
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  11 comentarios
Torsten
Torsten el 29 de Mzo. de 2024
Define
g = @(x,y,m,n) zeros(m,n)
in the script part
and use it as
Z = g(X,Y,size(X,1),size(X,2))
in your function.
Don't overcomplicate things - your code looks complicated enough.
Nilay Modi
Nilay Modi el 29 de Mzo. de 2024
it works now, after changing to
g = @(x,y) zeros(size(x));
graph_surface( ...
g, ...
xy_limit=2.5, ...
FaceColor='interp')

Iniciar sesión para comentar.


Steven Lord
Steven Lord el 29 de Mzo. de 2024
I am expecting Z to be zeros matrix of 10x10. But I am getting Z to be a 0 of 1x1.
Why?
Because that's what you told your function to return.
Based on your later comment, you don't want your function to return a 1-by-1 or even a fixed 10-by-10. You want it to return a zeros matrix the same size as the input. Correct?
f = @(X, Y) zeros(size(X));
X = ones(4)
X = 4×4
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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f(X, X)
ans = 4×4
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
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Y = ones(5, 8)
Y = 5×8
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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f(Y, Y)
ans = 5×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
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Z = 42
Z = 42
f(Z, Z)
ans = 0

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