Unrecognized function or variable 'del'.

n=0;

>> for del=0.0:0.4:pi

n=n+1;

pe(n)=1.2*sin(del);

Answer 1

[ScottB]

del is a native function:

Delete a ROS parameter - MATLAB del (mathworks.com)

Try renaming your variable. You also need and "end" statement at the end of your loop.

Answer 2

[Aquatris]

Not recommended but you can generally overwrite native variable/function names. I cannot reproduce your problem

n = 0;
for del=0.0:0.4:pi
n=n+1;
pe(n)=1.2*sin(del);
del % disp
end

del = 0

del = 0.4000

del = 0.8000

del = 1.2000

del = 1.6000

del = 2

del = 2.4000

del = 2.8000

Answer 3

[Star Strider]

That should actually work —

tic
n = 0;
for del=0.0:0.4:pi
    n=n+1;
    pe(n)=1.2*sin(del);
end
toc

Elapsed time is 0.026322 seconds.

pe

pe = 1x8

0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

A mnore efficient implementation would be —

tic
del=0.0:0.4:pi;
for n = 1:numel(del)
    pe(n) = 1.2*sin(del(n));
end
toc

Elapsed time is 0.002461 seconds.

pe

pe = 1x8

0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

However you can take advantage of MATLAB vectorisation capabilities and just use —

tic
del=0.0:0.4:pi;
pe = 1.2*sin(del);
toc

Elapsed time is 0.001995 seconds.

pe

pe = 1x8

0 0.4673 0.8608 1.1184 1.1995 1.0912 0.8106 0.4020

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

The vectorisation approach is morst efficient in this instance (and likely others as well).

See the documentation section on Vectorization for details.

.