file name recognition

I have a directory wich can containn files.A XOR files.B
I need to write code to dell if the extension is A or B and based on that assign myfunct=AA() or myfunct=BB()
any suggestions appreciated?

 Respuesta aceptada

Fangjun Jiang
Fangjun Jiang el 17 de Nov. de 2011

0 votos

[PATHSTR,NAME,EXT,VERSN] = FILEPARTS(FILE) returns the path, filename, extension and version for the specified file. FILEPARTS is platform dependent.

1 comentario

Baba
Baba el 17 de Nov. de 2011
since my directory only contains one type of files. How would I tell to grab, say, first file and and equate it to 'FILE'

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Más respuestas (1)

Walter Roberson
Walter Roberson el 17 de Nov. de 2011

0 votos

filelist = dir();
filelist([filelist.isdir]) = []; %remove . and ..
for K = 1 : length(filelist)
[pathstr, name, ext, versn] = fileparts(filelist(K).name);
if strcmp(ext,"A")
myfunct = AA();
else
myfunct = BB();
end
end

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el 17 de Nov. de 2011

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