I managed to fix the first one; I used "and" but it should've been "or" instead. I'm still stuck on the second.
Where is the issue in my "while" statement?
17 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I want to evaluate the first integer evenly divisible by 3 and 5 using a Matlab code. My attempt is the following:
n=1;
while mod(n,5)~=0 && mod(n,3)~=0
n=n+1;
end
n
I'm new to Matlab and wondering where the issue here is. The code returns n=3 for some reason. I also want to extend this to find the first number evenly divisible by 1-10, for which I wrote the following while loop which also did not return the expected value. Where is my error?
n=1;
while mod(n,1:10)~=0
n=n+1;
end
n
Thank you.
3 comentarios
Walter Roberson
el 29 de Jul. de 2017
found_solution = false;
n = 0;
while ~found_solution
n = n + 1;
found_solution = true;
for k = 1 : 10
if mod(n,k) ~= 0
found_solution = false;
break;
end
end
end
n
Respuestas (2)
the cyclist
el 29 de Jul. de 2017
Editada: the cyclist
el 29 de Jul. de 2017
In your second case, you are doing
mod(1,1)
then
mod(2,2)
then
mod(3,3)
and so on, because you are always incrementing n right along with k. Those mod functions are always equal to zero, so they always satisfy the while condition, so you get to n = 10.
0 comentarios
Teja Muppirala
el 30 de Jul. de 2017
You were on the right track. This gives 2520:
n=1;
while any( mod(n,1:10)~=0 )
n=n+1;
end
n
When your conditional has more than one element, all of them must be true for it to evaluate as true. This will return 'B' and 'C'.
if [1 1 1 0]
disp('A')
else
disp('B')
end
if [1 1 1 1]
disp('C')
else
disp('D')
end
0 comentarios
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!