Find the number of times a number is in an array for every column

Hi, this is probably quite simple but can't get my head around it. I have 8784 x 9 matrix and I want to find value <= 0 in this matrix for each column and save the answer as a new matrix of 1 x 9. I've started with this:

[nrow, ncol] = size (matrix)

for k = 1:ncol

newMatrix = find(matrix =>0)

end

This ends up giving me just 1 column instead of 9 columns. Eventually I want to use the number of times the value of 0 (or less) occurs in each column as part of my next calculation. Can anybody help? Thanks!

Answer 1

[Fangjun Jiang]

Hope this give you a clue

a=rand(3,9)-0.5;
b=a<=0;
c=sum(b)