About maximum value in matrix

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Mohamad Agung Prawira Negara
Mohamad Agung Prawira Negara el 6 de Ag. de 2018
Comentada: Stephen23 el 7 de Ag. de 2018
I have a problem regarding finding a maximum value from my matrix (largest element in the row)
I have matrix A shown bellow
I know that I can use
M=max(A,[],2)
Then I will get matrix M such that
But the answer I want is not that, what I want is that . The one that I want is
The answer that I want is the maximum value of each row ignoring the negativity of each value like shown in the matrix above.
I hope my question is clear enough.

Respuesta aceptada

Stephen23
Stephen23 el 6 de Ag. de 2018
Editada: Stephen23 el 6 de Ag. de 2018
This can be done using sub2ind:
A = [2,4,-1,0,-1;1,3,12,-3,2;-12,2,4,0,-1;2,4,0,-5,-2;3,-4,-1,0,8]
[~,C] = max(abs(A),[],2); % C = column indices
S = size(A);
R = 1:S(1); % R = row indices
X = sub2ind(S,R(:),C(:)); % X = linear indices
Z = A(X)
Giving
Z =
4
12
-12
-5
8
It would be nice if max etc. could return the linear indices, but that is what we have to work with. Note that you can also calculate the linear indices yourself, without sub2ind:
X = S(1)*(C-1)+(1:S(2)).'
  2 comentarios
Mohamad Agung Prawira Negara
Mohamad Agung Prawira Negara el 6 de Ag. de 2018
Thanks for the answer, it works for me
Stephen23
Stephen23 el 7 de Ag. de 2018
Another possibility:
>> A = [2,4,-1,0,-1;1,3,12,-3,2;-12,2,4,0,-1;2,4,0,-5,-2;3,-4,-1,0,8];
>> [C,X] = max(max(cat(9,A,-A),[],2),[],9);
>> C .* (3-2*X)
ans =
4
12
-12
-5
8

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Más respuestas (1)

Fangjun Jiang
Fangjun Jiang el 6 de Ag. de 2018
use abs() and note that the second return of max() gives the indices. See if you can figure it out.

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