How does Simulink Selector block work to extract dimension MxN matrix into 1xN row vectors?
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Jake Gonzalez
el 24 de Sept. de 2018
Comentada: Jake Gonzalez
el 25 de Sept. de 2018
Recently I was trying to take a 2x5 matrix signal and convert it into two 1x5 row vectors for further computation. To do so, I used the Simulink Selector block, and selected a 2 dimensional input (M of my MxN). Then to try and get just a row vector for dimension 1 and 2 respectively, I selected the Starting Index Option, and made sure that dimensional values were consistent (see image):
This setup works for the first row vector, but fails for the second row vector claiming the following error:
I eventually figured out how to split them into row vectors correctly via the following setup:
I am curious why the first setup works for the first row, but fails for the second row. Is this a bug, or do I have a fundamental misunderstanding of how this selector block is functioning? It seems odd that it would work in an inconsistent manner.
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Bish Erbas
el 24 de Sept. de 2018
That's because when the Starting index (dialog) option is used, Simulink selects the elements based on the Index column and Output Size. Your input has only 5 columns. If you set Index to 2 and Output Size to 5, you are telling Simulink to select columns 2 3 4 5 6 (size of 5). If your goal is to extract the last 4 column elements in the 2nd row, you can set output size to 4. Result would be 7 8 9 10.
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Fangjun Jiang
el 24 de Sept. de 2018
Are you sure? I tried as your example and there is no error. The error happened in "Selector1" yet the dialog show "Selector2" and "Selector3".
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Fangjun Jiang
el 24 de Sept. de 2018
The problem lies in the second dimension. The input is 2x5, so for the second dimension, if you starts with 2 but the output size is 5, then it requires 2x6 input. If you change the size from 5 to 4, then the error disappears.
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