comparing matices that contain numbers and NaNs

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antonet
antonet el 4 de Jul. de 2012
I have 2 cell matrices R and W and I want to check if they contain the same elements. Specifically, I want to compare R which is obtained from
[N,T,R] = xlsread( filename); %
with another matrix W.Both matrices are cell matrices and can also contain NaN entries.
My goal: If my calculations are correct then
kk=W(7 ,3:end); should contain the same elements with
zz1=R(7,3:end);
or zz2=R(8,3:end);
So to test this I do something like
if zz==xx1 | zz== xx2
'OK' else 'Not OK' EndThe problem is that
zz==xx1
??? Undefined function or method 'eq' for input arguments of type 'cell'.
So I use cell2mat(zz)==cell2mat(xx1) and it works.
But if zz and xx1 contain NaN then for some reason I cannot use the cell2mat() approach
I am looking for a general approach that will enable me to do that comparison whether I have NaN and numbers or only numbers’
thanks
  1 comentario
Jan
Jan el 5 de Jul. de 2012
@Readers: It seems like anonet wants to compare cells, which contain numerical and string values.

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Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 5 de Jul. de 2012
Editada: Andrei Bobrov el 5 de Jul. de 2012
variant of comparison cell arrays (edit)
A = {...
[84] [ 93] [ 109]
[99] [NaN] [ 62]
[29] [123] 'dgdgdg'};
B = {...
[84] [ 93] [ 109]
[99] [NaN] [ 62]
[29] [123] 'dgdgdg'};
A1=A;
B1=B;
A1(cellfun(@(x)all(isnan(x)),A)) = {0};
B1(cellfun(@(x)all(isnan(x)),B)) = {0};
out = isequal(A1,B1);
  4 comentarios
antonet
antonet el 5 de Jul. de 2012
Editada: antonet el 5 de Jul. de 2012
can i omit
A1=A;
B1=B;
so as to simlpy have
A = {...
[84] [ 93] [ 109]
[99] [NaN] [ 62]
[29] [123] 'dgdgdg'};
B = {...
[84] [ 93] [ 109]
[99] [NaN] [ 62]
[29] [123] 'dgdgdg'};
A(cellfun(@(x)all(isnan(x)),A)) = {0};
B(cellfun(@(x)all(isnan(x)),B)) = {0};
out = isequal(A,B)
thanks
Andrei Bobrov
Andrei Bobrov el 5 de Jul. de 2012
Hi Antonet! Thank you for "Accepted answer", but I mean that Jan's answer better.

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Más respuestas (2)

Jan
Jan el 5 de Jul. de 2012
C1 = {'String1', 23, -17, NaN, 1:29);
C2 = {'String2', 24, -17.3, 21, 1:30);
C3 = {'String1', 23, -17, NaN, 1:29);
% |C1==C2| fails!
isequalwithequalnans(C1, C2)
isequalwithequalnans(C1, C3)
I cannot test this currently. When NaNs should be assumed to be different, isequal would do it.
  4 comentarios
Teja Muppirala
Teja Muppirala el 5 de Jul. de 2012
On more recent releases, there is the ISEQUALN function so you don't have to write out ISEQUALWITHEQUALNANS
antonet
antonet el 5 de Jul. de 2012
what is +1 means?

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Kevin Claytor
Kevin Claytor el 4 de Jul. de 2012
My guess from searching the help docs for 'cell' gives;
m = cell2mat(c) converts a multidimensional cell array c with contents of the same data type into a single matrix, m.
  3 comentarios
Walter Roberson
Walter Roberson el 5 de Jul. de 2012
What do you want to have happen in the locations that contain strings? It is not possible for a numeric array to contain strings.
Jan
Jan el 5 de Jul. de 2012
@antonet: Please provide the necessary information in the original question, because readers in this forum will read it at first. Therefore you can edit the question.
The code you have posted is hard to read. Please read the instructions about code formatting again.

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