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Why wont this run? "Array indices must be positive integers or logical values."

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Steven Butts
Steven Butts el 5 de Feb. de 2020
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
clear all
close all
clc
L =.2;% H
C = 2.0*10^-6; %F
R1 = 1500; %Ohms
R2 = 1000; %Ohms
f = (1/(2*(pi)))*(L*C(((R1^2)*C-L)/((R2^2)*C-L)))^(1/2)
  1 comentario
Adam
Adam el 5 de Feb. de 2020
C(((R1^2)*C-L)/((R2^2)*C-L))
is not sensible code. All that stuff in the parentheses is being interpreted as an index into C, which is scalar anyway, but even if it wasn't I doubt that evaluates to an integer index.
Did you just miss out a * operator?

Respuestas (2)

Fangjun Jiang
Fangjun Jiang el 5 de Feb. de 2020
Most likely typo
f = (1/(2*(pi)))*(L*C*(((R1^2)*C-L)/((R2^2)*C-L)))^(1/2)

Guillaume
Guillaume el 5 de Feb. de 2020
"Why wont this run? "Array indices must be positive integers or logical values."
The clue is in the error message. Array indices... so you must have some indexing somewhere. Look at your equation:
.. C(((R1^2)*C-L)/((R2^2)*C-L))) ..
yep, you've got C(something). Looking at the something, it's very unlikely to be an integer index. Considering that C is scalar, it's very unlikely you meant to index C. Maybe you're missing an operator?
To make your expression more readable, I would recommend spacing out some terms. I would also recommend against using brackets when they're not needed:
f = 1/(2*pi) * L*C ?? sqrt((R1^2*C - L) / (R2^2*C - L));
%No idea what goes ^ there

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