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can anyone check this code?

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Atrolita afra
Atrolita afra el 2 de Abr. de 2020
Comentada: Ameer Hamza el 2 de Abr. de 2020
function l=LCR_CF(k,c,sigma)
%% pdf of process of various values of system parameters
for x=0:.0625:10
temp=0;
LCR=0;
ro=(x.^2/sigma);
ro=20*log10(ro);
for p=0:10
for n=0:p+1
% closed term expansion
b=nchoosek(p+(1/2),n);
% gamma term calculation
f=factorial(p);
g=(gamma(p+1))*(gamma(c));
g_ma=((ro.^(p+0.5))*(k.^c)*(2*sqrt(2*pi)))/(g*f);
% bessel function term calculation
z=2*sqrt(k*(1+ro));
K = besselk(p-n+c,z);
% Exponential term calculation
exponential=exp(-ro);
% Last term
q=(p-n+c)/2;
last_term=((k/(1+ro)).^q);
% Final pdf function
temp1= b*g_ma*K*exponential*last_term;
temp=temp+temp1;
end
LCR=LCR+temp;
end
l(1,x/(.0625)+1)=LCR;
end
THIS IS THE FUNCTION I AM TRYING TO PLOT BUT I AM GATTING AN ERROR ,""Undefined function 'LCR_CF' for input arguments of type 'double'.""
HOW CAN I SOLVE THIS?
I HAVE CALLED THIS FUNCTION BY THE FOLLOWING CODE:
clc
clear all
close all
syms x ;
%% For different values of k and c. Change the value of k and c according to figure.
sig=1;
y1=LCR_CF(0.2,1.5,sig); % Put the values of k,c,sig accordingly
y2=LCR_CF(0.5,1.5,sig);
y3=LCR_CF(1,1.5,sig);
y4=LCR_CF(1.5,1.5,sig);
y5=LCR_CF(.2,2,sig);
y6=LCR_CF(.5,2,sig);
y7=LCR_CF(1,2,sig);
y8=LCR_CF(1.5,2,sig);
%% Ploting data
x=0:0.0625:10;
figure
% plot(y1,x,'b',y2,x,'b',y3,x,'b',y4,x,'b',y5,x,'g--',...
% y6,x,'g--',y7,x,'g--',y8,x,'g--');
plot(x,y1,'b',x,y2,'b',x,y3,'b',x,y4,'b',x,y5,'g--',...
x,y6,'g--',x,y7,'g--',x,y8,'g--');
xlim([0 10]);
ylim([0 1]);
title('Normalized LCR');
xlabel('x');
ylabel('N(x)');
txt = {'Sigma=1','C=1.5, Solid Line', 'C=2, Dotted Line'};
text(6,6,txt);
txt = {'k=1.5'};
text(1,6,txt);
  13 comentarios
Atrolita afra
Atrolita afra el 2 de Abr. de 2020
Atrolita afra
Atrolita afra el 2 de Abr. de 2020
instead of infinity i was trying with 10

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Respuesta aceptada

Ameer Hamza
Ameer Hamza el 2 de Abr. de 2020
I have corrected the syntax issue in your code. The MATLAB function nchoosek does not work for fractional numbers. However, Now it gives infinity at 0 and also gives complex values. I am not sure whether this is correct or wrong.
function l=LCR_CF(k,c,sigma)
%% pdf of process of various values of system parameters
nck = @(n, k) gamma(n+1)./(gamma(k+1).*gamma(n-k+1));
X = 0:.0625:10;
l = zeros(size(X));
for i=1:numel(X)
x = X(i);
temp=0;
LCR=0;
ro=(x.^2/sigma);
ro=20*log10(ro);
for p=0:10
for n=0:p+1
% closed term expansion
b=nck(p+(1/2),n);
% gamma term calculation
f=factorial(p);
g=(gamma(p+1))*(gamma(c));
g_ma=((ro.^(p+0.5))*(k.^c)*(2*sqrt(2*pi)))/(g*f);
% bessel function term calculation
z=2*sqrt(k*(1+ro));
K = besselk(p-n+c,z);
% Exponential term calculation
exponential=exp(-ro);
% Last term
q=(p-n+c)/2;
last_term=((k/(1+ro)).^q);
% Final pdf function
temp1= b*g_ma*K*exponential*last_term;
temp=temp+temp1;
end
LCR=LCR+temp;
end
l(i)=LCR;
end
  3 comentarios
Atrolita afra
Atrolita afra el 2 de Abr. de 2020
Oh i got your logic thanks for the infornation. though i don't know wheather it is the correct figure or not but i got that i will manage the rest !
Ameer Hamza
Ameer Hamza el 2 de Abr. de 2020
Glad to be of help. Best of luck for your project.

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