How do I create a matrix with all binary combinations?
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Christian P
el 13 de Mayo de 2020
Comentada: Pranay Agarwal
el 2 de Dic. de 2022
Hi
I want to create a matrix with all binary combinations. If N is the length of the binary code, there would be possible combinations. Below are , and the 16 possible binary combinations are displayed.
1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0
1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 0
1 1 0 0 1 1 0 0 1 1 0 0 1 1 0 0
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
How can I create such a matrix automatically? I don't really care which order they are in, as long as every combination is present, and N is a variable.
Thanks in advance.
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the cyclist
el 13 de Mayo de 2020
There's an incredible obfuscated hack for this:
N = 4;
dec2bin(0:2^N-1)' - '0'
Más respuestas (2)
James Tursa
el 13 de Mayo de 2020
Editada: James Tursa
el 13 de Mayo de 2020
dec2bin(0:2^N-1) - '0'
Note that this is only practical for relatively small values of N. Even moderatly large N can cause this to exceed your available memory.
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Voss
el 1 de Dic. de 2022
N = 4; % length
base = 3;
output = dec2base(0:base^N-1,base)-'0';
disp(output);
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