Sum of a Series, Help!
Mostrar comentarios más antiguos
Hi i have had a look around for some help on multiple variables using sum and sigma.
Couldnt quite understand how to apply those examples to my problem.
And I have got to write out this function and be able to plot it on a graph.
Being that n is 1,2 or 3 (on the same graph)
Pn(x) = 
5 comentarios
Nathan Barnes
el 9 de Jul. de 2020
madhan ravi
el 9 de Jul. de 2020
Why?
Stephen23
el 10 de Jul. de 2020
Original question by Nathan Barnes retrieved from Google Cache:
"Sum of a Series, Help!"
Hi i have had a look around for some help on multiple variables using sum and sigma.
Couldnt quite understand how to apply those examples to my problem.
And I have got to write out this function and be able to plot it on a graph.
Being that n is 1,2 or 3 (on the same graph)

madhan ravi
el 10 de Jul. de 2020
Thank you Stephen!
Rena Berman
el 22 de Jul. de 2020
(Answers Dev) Restored edit
Respuestas (2)
David Hill
el 9 de Jul. de 2020
Not sure exactly what you are asking.
x=0:.1:10;
for n=1:3
S(n,:)=arrayfun(@(i)sum(repmat(-1,1,n+1).^(0:n)./(2*(0:n)+1).*repmat(i,1,n+1).^(2*(0:n)+1)),x);
end
subplot(3,1,1);
plot(x,S(1,:));
subplot(3,1,2);
plot(x,S(2,:));
subplot(3,1,3);
plot(x,S(3,:));
3 comentarios
madhan ravi
el 9 de Jul. de 2020
See after providing a complete solution usually the OP deletes the question. That’s why it’s better to provide hints than a complete solution.
Nathan Barnes
el 9 de Jul. de 2020
Rik
el 9 de Jul. de 2020
Then why did you delete it?
Boxn Hen
el 9 de Jul. de 2020
Hope to help you as follow.Ps:I just use 'for' to sum all seperate results.
function result=SumAndSigma(x,n)
r(1)=0;
for i=0:n
r(i+2)=r(i+1)+((-1)^i/(2*i+1)).*x.^(2*i+1)% There are n+1 elements and the first one is 0.
end
result=r(2:end);
end
And input x and n to the function SumAndSIgma.
%for example:x=3;n=5
x=3;n=5;
result=SumAndSigma(x,n)
data=0:n;
plot(data,result);

Categorías
Más información sobre Startup and Shutdown en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!