how to create a random integernumbers with conditions?

2 visualizaciones (últimos 30 días)
SM
SM el 16 de Jul. de 2020
Comentada: SM el 16 de Jul. de 2020
I just want to create an array at random which size will be 1 by sum([4 3 3]). The array contains 1 at 4 times, 2 at 3 times and 3 at 3 times. The result will be
A=[1 2 1 3 2 3 1 1 2 3], ie, random.
How can I generate it in the smart way?

Respuesta aceptada

madhan ravi
madhan ravi el 16 de Jul. de 2020
ix = [4, 3, 3];
A = repelem(1:3, ix);
A(randperm(numel(A)))
  1 comentario
SM
SM el 16 de Jul. de 2020
Thank You, Ravi. It is perfectly alright for my problem.

Iniciar sesión para comentar.

Más respuestas (1)

David Hill
David Hill el 16 de Jul. de 2020
A=[4 3 3];
a=[];
for k=1:length(A)
a=[a,repmat(k,1,A(k))];
end
for k=1:5
a=a(randperm(length(a)));%you don't necessary have to do this loop, you could do it just once
end
  1 comentario
SM
SM el 16 de Jul. de 2020
Thank you. It is also suitable for my problem but i try to avoid using loop.

Iniciar sesión para comentar.

Categorías

Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by