How to collapse within a column vector

Hello,
I am trying to collapse a long column to a shorter one by suming across elements. For instance, if I have:
x =
1
2
3
4
5
6
7
8
9
I would like to sum up every three elements and arrive at:
y= 6
15
24
This is basically the 'collapse' function in Stata but I'm struggling to do it in Matlab. Thanks for your advide.

 Respuesta aceptada

Arthur Roué
Arthur Roué el 17 de Jul. de 2020
Editada: Arthur Roué el 17 de Jul. de 2020
You can use the sum function after reshape your vector into a matrix
vX = 1:9;
Interval = 3;
mX = reshape(vX, Interval, numel(vX)/Interval)
mX =
1 4 7
2 5 8
3 6 9
sum(mX)
ans =
6 15 24
/!\ reshape() won't work if the number of elements in vX is not a multiple of Interval

4 comentarios

Ara Jo
Ara Jo el 17 de Jul. de 2020
Thank you very much -- it works well!
Ara Jo
Ara Jo el 18 de Jul. de 2020
A related question is.. how would you do it if you had a matrix rather than a column vector? For instance, if I have a 6 by 3 matrix X
X =
1 4 7
2 5 8
3 6 9
1 4 7
2 5 8
3 6 9
How could I turn this into 3 by 3 by suming up every two elements in each column and get:
Y=
3 9 15
4 10 16
5 11 17
I tried to use reshape again and it seems the matrix is sliced in an inconvinient way.. Thank you very much for your time!
How about:
X = [1 4 7; 2 5 8; 3 6 9; 1 4 7; 2 5 8; 3 6 9];
X = X(:);
X = reshape(X,2,length(X)/2);
Y = sum(X);
Y = reshape(Y, 3, length(Y)/3);
Ara Jo
Ara Jo el 18 de Jul. de 2020
Works perfectly - thank you very much!

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Más respuestas (1)

Alan Stevens
Alan Stevens el 17 de Jul. de 2020
One possibility is:
x = 1:12;
for i = 1:length(x)/3
p = 3*(i-1)+1;
y(i) = sum(x(p:p+2));
end

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el 17 de Jul. de 2020

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el 18 de Jul. de 2020

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