Smooth decay of a function
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I have a function which dies of quickely. I need this function to smoothly decay off to 0 . Is there any way in Matlab to make that happen?
4 comentarios
Image Analyst
el 26 de Jul. de 2020
Please give values for everything in that alphabet soup. And include a screenshot of what you got, and what you'd like to achieve, but only after you read this link.
T = linspace(-5, 5, 500);
Tc = 3;
y = 2;
a = 7;
b = 6;
m = ((-b + (((b*b)-(4*y*a*(T-Tc))).^0.5))/(2*y)).^0.5;
subplot(2, 1, 1);
plot(T, real(m), 'b-', 'LineWidth', 2);
title('Real(m) vs. T', 'FontSize', 20);
grid on;
xlabel('T', 'FontSize', 20);
ylabel('real(m)', 'FontSize', 20);
% For T>Tc, m(T) becomes complex so m(T>Tc)=0
% Hence I want m(T) to smoothly decay to 0 for T>Tc
subplot(2, 1, 2);
plot(T, imag(m), 'b-', 'LineWidth', 2);
title('Imag(m) vs. T', 'FontSize', 20);
grid on;
xlabel('T', 'FontSize', 20);
ylabel('imag(m)', 'FontSize', 20);

For the random values I chose, it does look like the curve approaches the Tc point smoothly. What does it look like for you, with your values???
Respuestas (1)
Alan Stevens
el 26 de Jul. de 2020
Editada: Alan Stevens
el 26 de Jul. de 2020
How about writing a function like:
function mfn = mvalue(T,Tc,a,b,y)
disc = b^2 - 4*y*a*(T - Tc);
quad = -b + disc^0.5/(2*y);
if disc>0 && quad>0
mfn = quad^0.5;
else
mfn = 0;
end
end
and then calling
m(i) = mvalue(T(i), Tc, a, b, y);
5 comentarios
Alan Stevens
el 26 de Jul. de 2020
Editada: Alan Stevens
el 26 de Jul. de 2020
Impossible to tell without knowing about the system you are modelling. Mathematically you could probably multiply m by some sort of exponential decay term. However, would that make sense in the context of your model?
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