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Error using cellstr. Shows error for element that doesn't exist.

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Jannat Manchanda
Jannat Manchanda el 19 de Ag. de 2020
Editada: Fangjun Jiang el 20 de Ag. de 2020
I am getting the following error:
Error using cellstr (line 44) Element 154 is not a string scalar or character array. All elements of cell input must be string scalars or character arrays.
But the array I am trying to conver has size: [153 4]
I am trying to display the data to MATLAB Table (App Designer).
I am saving the data into a cell matrix form then converting to string to display in a table in the app.
TblAllInfo=[app.FMain',ChannelNameFinal',LocationFinal',ChannelFilter'];
app.UITableAll.Data=cellstr(TblAllInfo);

Respuestas (3)

Fangjun Jiang
Fangjun Jiang el 19 de Ag. de 2020
I can duplicate the error using this simple example. So the problem is TblAllInfo{1,2}. It is the 154th element. It is not a char array.
a =
3×2 cell array
{'a'} {[1]}
{'a'} {[2]}
{'c'} {[3]}
>> cellstr(a)
Error using cellstr (line 44)
Element 4 is not a string scalar or character array. All elements of cell input must be string
scalars or character arrays.
  2 comentarios
Jannat Manchanda
Jannat Manchanda el 19 de Ag. de 2020
Yes, exactly this. How to resolve it ?
Fangjun Jiang
Fangjun Jiang el 20 de Ag. de 2020
Editada: Fangjun Jiang el 20 de Ag. de 2020
The method depends on the data types. Why don't you show some example data?
In my example data, you could use cellstr(string(a))

Iniciar sesión para comentar.


Jannat Manchanda
Jannat Manchanda el 19 de Ag. de 2020
For now I have added the following code, so that I can proceed with my work. If anyone has any better answers. TIA :)
for i=1:length(TblAllInfo)
Data1{i}=string(TblAllInfo(i,:));
Data2{i,:}=cellstr(Data1{1,i});
Data3(i,:)=Data2{i};
end
app.UITableAll.Data=Data3;

Walter Roberson
Walter Roberson el 20 de Ag. de 2020
app.UITableAll.Data=cellstr(TblAllInfo(:,1));

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