Hi, I am having some trouble with a plot. I am trying to plot pressure vs. time using an equation for pressure with respect to time. Whenever I plot this I get a blank graph, so i'm not sure what the problem is. I appreciate any help!
8 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Po = 400000;
Patm = 101325;
rhowater = 1000;
Vo = .00133333;
Anoz = pi*(.010668)^2;
syms P t
P = Po + (((-1.4*P*((P/Po)^(5/7)))/Vo)*(Anoz*sqrt((P-Patm)/rhowater)))*t;
Eqn = solve(P,t);
Peq = Eqn;
fplot(Peq,[0 1])
ylim ([0 450000])
xlabel('time (s) ')
ylabel('Pressure (Pa) ')
0 comentarios
Respuestas (2)
VBBV
el 6 de Ag. de 2024
Editada: VBBV
el 6 de Ag. de 2024
@Sarah Fries Try using the vpasolve function and solve the equation for well defined input time interval. In your code, you were trying to solve the equation for time variable, and contains two unknown variables, i.e. P and t the first variable is Pressure, which needs to be evaluated (solved) while the second variable is just time which can be defined arbitrarily to check how the pressure varies with time.
Po = 400000;
Patm = 101325;
rhowater = 1000;
Vo = .00133333;
Anoz = pi*(.010668)^2;
t = 0:1:20; % define a time vector
syms P
for k = 1:numel(t)
eqn = P-(Po + (((-1.4*P*((P/Po)^(5/7)))/Vo)*(Anoz*sqrt((P-Patm)/rhowater))).*t(k))==0;
sol(k) = vpasolve(eqn,P); % try with vpasolve
end
% use the simple plot function
plot(t,double(sol))
ylim ([0 450000]); grid
xlabel('time (s) ')
ylabel('Pressure (Pa) ')
0 comentarios
madhan ravi
el 27 de Sept. de 2020
Editada: madhan ravi
el 27 de Sept. de 2020
fplot(Peq)
0 comentarios
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!