Adding Plotting to bisection method

3 visualizaciones (últimos 30 días)
gracias claude
gracias claude el 13 de Feb. de 2021
Comentada: Alan Stevens el 13 de Feb. de 2021
Not sure what the c is in this bisection method. Also I would like to add plotting of the intervals
function [x,e] = MyBisectFunc(f, a1,b1, number)
format long
c1 = f(a1); d1 = f(b1);
if c1*d1 > 0.0
error ('Func has same sign at both endpoints')
end
for i = 1:number
x = (a1 + b1) /2;
y = f(x);
disp([x,y])
if y == 0.0
e = 0
break
end
if c*y < 0
b = x
else
a = x
end
end
x = (a1 + b1)/2;
e = (b1 - a1) /2;

Respuestas (1)

Alan Stevens
Alan Stevens el 13 de Feb. de 2021
Like so:
f = @(x) x^2 - 2; % arbitrary function
a1 = 0; b1 = 1.8; % initial end-points
c1 = f(a1); d1 = f(b1);
if c1*d1 > 0.0
error ('Func has same sign at both endpoints')
end
number = 20;
for i = 1:number
c1 = f(a1); d1 = f(b1);
if c1*d1 > 0.0
error ('Func has same sign at both endpoints')
end
x = (a1 + b1) /2;
y = f(x);
disp([x,y])
if abs(y) < 10^-8
break
end
if c1*y < 0 % c1 not c
b1 = x;
else
a1 = x;
end
end
  6 comentarios
gracias claude
gracias claude el 13 de Feb. de 2021
not very familar with the syntax
Alan Stevens
Alan Stevens el 13 de Feb. de 2021
This section
if abs(y) < 10^-8
break
end
breaks out of the loop if the condition is met. Probably best to remove it if you want to plot the intervals. You'll need to do something like:
f = @(x) x^2 - 2; % arbitrary function
number = 20; % number of iterations
lo = zeros(1,number); % initialise vector
hi = zeros(1,number);
lo(1) = 0;
hi(1) = 1.8;
for i = 1:number-1
flo = f(lo(i)); fhi = f(hi(i));
if flo*fhi > 0.0
error ('Func has same sign at both endpoints')
end
mid = (lo(i) + hi(i)) /2;
fmid = f(mid);
if flo*fmid < 0 % c1 not c
hi(i+1) = mid;
lo(i+1) = lo(i);
else
lo(i+1) = mid;
hi(i+1) = hi(i);
end
end
disp([mid fmid])
plot(1:number,abs(hi-lo),'o'),grid
xlabel('iteration number'), ylabel('interval')

Iniciar sesión para comentar.

Categorías

Más información sobre Graphics Objects en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by