Summing two binary vectors
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Neeraj Chimwal
el 24 de Mzo. de 2021
Comentada: Adam Danz
el 25 de Mzo. de 2021
How can I add two binary vector say a= 1 0 1, b= 1 1 0?
Using simply '+' gives decimal output. I want the summation in binary.
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Respuesta aceptada
Fangjun Jiang
el 24 de Mzo. de 2021
Editada: Fangjun Jiang
el 24 de Mzo. de 2021
%%
a = [1 0 1];
b = [1 1 0];
s=dec2bin(bin2dec(num2str(a))+bin2dec(num2str(b)))
out=str2num(s(:))
out =
1
0
1
1
Más respuestas (1)
Adam Danz
el 24 de Mzo. de 2021
Editada: Adam Danz
el 24 de Mzo. de 2021
y = sumbin(a,b) adds two binary values a and b represented by boolean row vectors (1/0, true/false) and returns the results y as a boolean row vector.
log2dec(v) is a helper function called by sumbin() and converts the boolean vectors to binary strings and then to the decimal representation.
Demo:
a = [1 0 1]; % = 5
b = [1 1 0]; % = 6
log2dec = @(v)bin2dec(num2str(v));
sumbin = @(a,b)dec2bin(sum([log2dec(a), log2dec(b)]))-'0';
sumbin(a,b) % = 11
If you want to add more than 2 binary numbers in the form of boolean vectors,
y = sumbin(a,b,...,n) receives any number of boolean row vectors (1/0, true/false) and returns the results y as a boolean row vector.
a = [1 0 1]; % = 5
b = [1 1 0]; % = 6
c = [1]; % = 1
d = [1 1 1]; % = 7
log2dec = @(v)bin2dec(num2str(v));
sumbin = @(varargin)dec2bin(sum(cellfun(log2dec, varargin)))-'0';
sumbin(a,b,c,d) % = 19
2 comentarios
Adam Danz
el 25 de Mzo. de 2021
@Neeraj Chimwal just FYI, the first part of my answer and Fangjun Jiang's answer are practically the same, there's very little difference.
The second part of my answer shows how to extend the summation to more than 2 binary vectors.
All vectors are arrays but not all arrays are vectors. A vector is 2D with one dimention equal to 1.
These are vectors
A = [1 0 1];
size(A)
B = [1;0;1];
size(B)
These are arrays that are not vectors
C = rand(2,3);
size(C)
D = rand(2,3,4);
size(D)
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