How do I add to a cell array based on logicals?

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Mitch Hezel
Mitch Hezel el 22 de Abr. de 2021
Comentada: Mitch Hezel el 22 de Abr. de 2021
I have two arrays, A and B.
A is an array of random numbers. B is an array of logicals, either 0 or 1. A is the same length as B.
For as long as B is 0, I want to add the data from A at those indices to a cell in a separate cell array.
for example,
A = [1 2 3 4 5 6 7 8 9 10]
B = [1 0 0 0 1 0 0 0 1 0].
The code should output C, where C{1} = [2,3,4], C{2} = [6 7 8], C{3} = 10. How should I accomplish that?
I'm currently doing it with a bunch of for loops which misses the last chunk of data, that is, it misses data in the event B doesn't end in 1.

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David Hill
David Hill el 22 de Abr. de 2021
There might be an easier way. Here is one with a single loop.
b=num2str(B);
b=b(b~=' ');
[idx1,idx2]=regexp(b,'[0]+');
for k=1:length(idx1)
C{k}=A(idx1(k):idx2(k));
end
  2 comentarios
Mitch Hezel
Mitch Hezel el 22 de Abr. de 2021
Editada: Mitch Hezel el 22 de Abr. de 2021
Looks like that actually works. The only change I had to make was changing b to be a row vector, since regexp is throwing an error if it isn't. Thanks dude! Edit: Ah, realizing that's probably my fault since I made it seem like my data was in row vectors with the example. Either way, it's working.
Mitch Hezel
Mitch Hezel el 22 de Abr. de 2021
Interestingly, this code is cleaner than my code (by probably a factor of 3 or more) but it is much slower. Is regexp a slow operation?

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